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3+22.5x-4.9x^2=0
a = -4.9; b = 22.5; c = +3;
Δ = b2-4ac
Δ = 22.52-4·(-4.9)·3
Δ = 565.05
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22.5)-\sqrt{565.05}}{2*-4.9}=\frac{-22.5-\sqrt{565.05}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22.5)+\sqrt{565.05}}{2*-4.9}=\frac{-22.5+\sqrt{565.05}}{-9.8} $
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